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If A,b,c,d Are In G.P , Then (a+b+c+d)^2 Is Equal To
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In A G.P. , T2+t5=216 And T4:t6 = 1:4 And All Terms Are Integers, Then It First Term Is
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If The N^th Term Of Geometric Progression 5, -5/2,5/4,-5/8,.....is 5/1024, Then The Valuable Of N Is
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The Product Of Three Geometric Means Between 4 And 1/4 Will Be
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If N Geometric Means Be Inserted Between A And B Then The N^th Geometric Mean Will Be
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The Sum Of 100 Terms Of The Series .9+.09+.009. ...will Be
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If The Ratio Of The Sum Of First Three Terms And The Sum Of First Six Terms Of A G.P. Be 125:152, Then The Common Ratio R Is
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7^th Term Of The Sequence √2, √10, 5√2 ....is
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The Number Which Should Be Added To The Number 2, 14, 62, So That The Resulting Number May Be In G.P. Is
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If A,b,c, Are In G.P., Then
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0 votes0 answer148 views
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If In A Geometric Progression {An}, A1=3, An. = 96 And Sn =189 Then The Value Of N Is
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The Solution Of The Equation 1+a+ A^+a^3+ .......+a^x = (1+a) (1+a^2)(1+a^4) Is Given By X Is Equal To
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For A Sequence Less Than An Greater Than , A1 = 2 And An + 1 / An = 1/3. Then Siqma Ar Is
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If The Sum Of Three Terms Of G.P. Is 19 And Product Is 216, Then The Common Ratio Of The Series Is
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If The Sum Of An Infinite G.P. Be 9 And The Sum Of First Two Terms Be 5 , Then The Common Ratio Is
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If Logx A, A^x/2 And Log B X Are In G.P. , Then X =
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The First And Last Term Of A G.P. Are A And L Respectively , R Being Its Common Ratio , Then The Number Of Terms In This G.P. Is
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If X, 2x +2, 3x+3, Are In G. P. , Then The Fourth Term Is
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The Sum Of A G.P. With Common Ratio 3 Is 364, And Last Term Is 243 , Then The Number Of Terms Is
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The First Term Of A G.P. Is 7 The Last Term Is 448 And Sum Of All Term Is 889, Then The Common Ratio Is
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The Product Of N Positive Number Is Unity . Their Sum Is
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The Third Term Of G.P. Is The Square Of First Term . If The Second Term Is 8 , Then The 6^th Term Is
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If The 10 ^ Th Term Of Geometric Progression Is 9 And 4th Term Is 4 , Then Its 7th Term Is
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Modified 5 Year Ago
